From 2a7bc10f6c011d19fb3b0e73068f7e1a9c30ace0 Mon Sep 17 00:00:00 2001 From: Raphael McSinyx Date: Sat, 8 Oct 2016 09:56:43 +0700 Subject: Initial commit --- daily/286easy/problem.html | 25 +++++++++++++++++++++++++ 1 file changed, 25 insertions(+) create mode 100644 daily/286easy/problem.html (limited to 'daily/286easy/problem.html') diff --git a/daily/286easy/problem.html b/daily/286easy/problem.html new file mode 100644 index 0000000..362cc50 --- /dev/null +++ b/daily/286easy/problem.html @@ -0,0 +1,25 @@ +

Description

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Nearly everyone is familiar with the factorial operator in math. 5! yields 120 because factorial means "multiply successive terms where each are one less than the previous":

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5! -> 5 * 4 * 3 * 2 * 1 -> 120
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Simple enough.

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Now let's reverse it. Could you write a function that tells us that "120" is "5!"?

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Hint: The strategy is pretty straightforward, just divide the term by successively larger terms until you get to "1" as the resultant:

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120 -> 120/2 -> 60/3 -> 20/4 -> 5/5 -> 1 => 5!
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Sample Input

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You'll be given a single integer, one per line. Examples:

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120
+150
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Sample Output

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Your program should report what each number is as a factorial, or "NONE" if it's not legitimately a factorial. Examples:

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120 = 5!
+150   NONE
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Challenge Input

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3628800
+479001600
+6
+18
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Challenge Output

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3628800 = 10!
+479001600 = 12!
+6 = 3!
+18  NONE
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