From 4bc9c7d398bddca1e7ab1072a02b7a22f773cb81 Mon Sep 17 00:00:00 2001 From: Raphael McSinyx Date: Sat, 8 Oct 2016 20:14:23 +0700 Subject: Update /r/dailyprogrammer challenge #286 [Easy] --- daily/286easy/problem.html | 25 ------------------------- 1 file changed, 25 deletions(-) delete mode 100644 daily/286easy/problem.html (limited to 'daily/286easy/problem.html') diff --git a/daily/286easy/problem.html b/daily/286easy/problem.html deleted file mode 100644 index 362cc50..0000000 --- a/daily/286easy/problem.html +++ /dev/null @@ -1,25 +0,0 @@ -

Description

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Nearly everyone is familiar with the factorial operator in math. 5! yields 120 because factorial means "multiply successive terms where each are one less than the previous":

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5! -> 5 * 4 * 3 * 2 * 1 -> 120
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Simple enough.

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Now let's reverse it. Could you write a function that tells us that "120" is "5!"?

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Hint: The strategy is pretty straightforward, just divide the term by successively larger terms until you get to "1" as the resultant:

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120 -> 120/2 -> 60/3 -> 20/4 -> 5/5 -> 1 => 5!
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Sample Input

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You'll be given a single integer, one per line. Examples:

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120
-150
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Sample Output

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Your program should report what each number is as a factorial, or "NONE" if it's not legitimately a factorial. Examples:

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120 = 5!
-150   NONE
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Challenge Input

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3628800
-479001600
-6
-18
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Challenge Output

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3628800 = 10!
-479001600 = 12!
-6 = 3!
-18  NONE
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