type id = int module ISet = Set.Make (struct type t = id let compare = compare end) type unop = Not type binop = | Add | Sub | Le | Ge | Lt | Gt | Eq | Ne type phi = { pjmp: id; pvar: int } type instr = | INop | ICon of int | IUop of unop * id | IBop of id * binop * id | IBrz of id * id * id | IJmp of id | IPhi of phi list (* Phi nodes must be at the join of branches in the control flow graph, if n branches join, the phi node must have n elements in its list that indicate the value to merge from each of the branches. The id given in each of *) type prog = instr array (* Here, we analyze a program backwards to compute the liveness of all variables. We assume that all phi nodes are placed correctly. *) let liveness p = (* The idea is now to reach a fixpoint by applying the same backward liveness propagation a sufficient number of times. The [changed] variable will tell us when we reached the fixpoint, it is reset to false at each iteration. *) let changed = ref true in let liveout = Array.make (Array.length p) ISet.empty in let setlive v l = (* Extend the liveness of v to l. *) if not (ISet.mem v liveout.(l)) then begin changed := true; liveout.(l) <- ISet.add v liveout.(l); end in let succs i = (* Retreive the successor nodes of i. *) if i = Array.length p -1 then [] else match p.(i) with | IBrz (_, i1, i2) -> [i1; i2] | IJmp i1 -> [i1] | _ -> [i+1] in let gen i = ISet.of_list (* Get the Gen set of i. *) begin match p.(i) with | IUop (_, i1) -> [i1] | IBop (i1, _, i2) -> [i1; i2] | IPhi l -> List.iter (fun {pjmp; pvar} -> setlive pvar pjmp ) l; [] | _ -> [] end in let livein i = (* Get the live In set of i. *) let s = liveout.(i) in let s = ISet.union s (gen i) in ISet.remove i s in (* The fixpoint computation. *) while !changed do changed := false; for i = Array.length p -1 downto 0 do (* Collect live Ins of all successor blocks. *) let live = List.fold_left (fun live i' -> ISet.union live (livein i') ) ISet.empty (succs i) in ISet.iter (fun i' -> setlive i' i ) live done done; liveout (* Testing. *) let parse src = let blocks = Hashtbl.create 31 in let rec addlbl idx l = let l = String.trim l in try let il = String.index l ':' in let lbl = String.sub l 0 il in Hashtbl.add blocks lbl idx; let l = String.sub l (il+1) (String.length l -(il+1)) in addlbl idx l with Not_found -> l ^ " " in let src = List.mapi addlbl src in let p = Array.make (List.length src) INop in List.iteri (fun idx l -> let fail s = failwith (Printf.sprintf "line %d: %s" (idx+1) s) in let tok = let p = ref 0 in fun () -> try while l.[!p] = ' ' do incr p done; let p0 = !p in while l.[!p] <> ' ' do incr p done; String.sub l p0 (!p - p0) with _ -> fail "token expected" in let id () = let v = tok () in try Hashtbl.find blocks v with _ -> fail ("unknown variable " ^ v) in let instr = if l = " " then INop else let bop o = let i1 = id () in let i2 = id () in IBop (i1, o, i2) in match tok () with | "con" -> ICon (int_of_string (tok ())) | "not" -> IUop (Not, id ()) | "add" -> bop Add | "sub" -> bop Sub | "cle" -> bop Le | "cge" -> bop Ge | "clt" -> bop Lt | "cgt" -> bop Gt | "ceq" -> bop Eq | "cne" -> bop Ne | "phi" -> let exp t = let t' = tok () in if t' <> t then fail ("unexpected " ^ t') in let rec f () = match tok () with | "[" -> let pjmp = id () in let pvar = id () in exp "]"; {pjmp; pvar} :: f () | "." -> [] | t -> fail ("unexpected " ^ t) in IPhi (f ()) | "brz" -> let v = id () in let bz = id () in let bn = id () in IBrz (v, bz, bn) | "jmp" -> IJmp (id ()) | i -> fail ("invalid " ^ i) in p.(idx) <- instr ) src; p let t_fact = parse [ "k0: con 0" ; "ni: con 1234" ; "k1: con 1" ; "n0: phi [ jmp n1 ] [ k1 ni ] ." ; "n1: sub n0 k1" ; "jmp: brz n1 end n0" ; "end:" ] (* The following program has irreducible control-flow. The control flow is pictured below. +--b1 <- defs r0, r1 | | b2 b3 | | \ b4<-+ <- uses r0 \ | | +--b5 | <- uses r1 | | | b7 b6--+ A simple implementation (that work for non- irreducible control flows) proceeds backwards, it would successfully make r1 live in b2 and b3 but r0 would fail to be live in b2. It would become live for the loop b4-b5-b6 when reaching the loop header b4, but the simple algorithm would not propagate back to b2. *) let t_irred = parse [ "k0: con 0" ; "r0: con 1" ; "r1: con 2" ; "b1: brz k0 b2 b3" ; "b2: jmp b5" ; "b3:" ; "b4: add r0 k0" ; "b50: add r1 k0" ; "b5: brz k0 b6 b7" ; "b6: jmp b4" ; "b7:" ] let _ = let open Printf in let s = liveness t_irred in for i = 0 to Array.length s-1 do printf "%04d:" i; ISet.iter (printf " %04d") s.(i); printf "\n"; done