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authorRaphael McSinyx <vn.mcsinyx@gmail.com>2016-10-08 20:14:23 +0700
committerRaphael McSinyx <vn.mcsinyx@gmail.com>2016-10-08 20:14:23 +0700
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Update /r/dailyprogrammer challenge #286 [Easy]
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-# Description
-
-Nearly everyone is familiar with the factorial operator in math. 5! yields 120 because factorial means "multiply successive terms where each are one less than the previous":
-
-    5! -> 5 * 4 * 3 * 2 * 1 -> 120
-
-Simple enough. 
-
-Now let's reverse it. Could you write a function that tells us that "120" is "5!"? 
-
-Hint: The strategy is pretty straightforward, just divide the term by successively larger terms until you get to "1" as the resultant:
-
-    120 -> 120/2 -> 60/3 -> 20/4 -> 5/5 -> 1 => 5!
-
-# Sample Input
-
-You'll be given a single integer, one per line. Examples:
-
-    120
-    150
-
-# Sample Output
-
-Your program should report what each number is as a factorial, or "NONE" if it's not legitimately a factorial. Examples:
-
-    120 = 5!
-    150   NONE
-
-# Challenge Input
-
-    3628800
-    479001600
-    6
-    18
-
-# Challenge Output
-
-    3628800 = 10!
-    479001600 = 12!
-    6 = 3!
-    18  NONE