1 files changed, 33 insertions, 0 deletions
diff --git a/usth/ICT2.1/final/problem1.c b/usth/ICT2.1/final/problem1.c
new file mode 100644
index 0000000..dce5ca7
--- /dev/null
+++ b/usth/ICT2.1/final/problem1.c
@@ -0,0 +1,33 @@
+/* Read a natural number from stdin and print its divisors to stdout */
+#include <stdio.h>
+
+/* Print all divisors of the given natural number n. */
+void print_divisors(int n, int i)
+{
+	if (i * i == n)
+		printf("%d\n", i);		/* Θ(1) */
+	if (i * i >= n)
+		return;				/* Θ(1) */
+	if (n % i == 0)
+		printf("%d\n%d\n", i, n / i);	/* Θ(1) */
+	print_divisors(n, i + 1);
+}
+
+/*
+ * Complexity analysis:
+ * Let T(n, i) be the time complexity of print_divisors, it is obvious that
+ *     T(n, i) = Θ(1) if i*i >= n
+ *     T(n, i) = T(n, i + 1) + Θ(1)
+ * Thus T(n, 1) = sum(Θ(1) for i from 1 to ceil(sqrt(n))) = Θ(sqrt(n))
+ * or the overall time complexity of the call from main is Θ(sqrt(n))
+ * on all scenarios.
+ */
+int main()
+{
+	int n;
+
+	scanf("%d", &n);
+	print_divisors(n, 1);
+
+	return 0;
+}